How exactly to Calculate Cement, Coarse and sand Aggregate Quantity within Concrete?



We've already discussed Nominal Combine of Concrete and Blend Proportions.

For those who have skipped that please go on and read that. We will wait for you.

It’s time for a few calculations.

In this article, we will explain “How to Calculate Cement Volume and its own ingredients?â€?*************)

If it's a volume, twe understand there must end up being 3 dimensions then,Length, Height, Width or even Breadth.

We covered some Simple SURFACE and Volume Formulas.

For Slab, If we have to calculate the concrete quantity,

Volume = Size X Breadth X Width/Thickness = 5 X 3 X 0.125 = 3.75 m3

For Beam, If we have to calculate the concrete quantity,

Typical Beam

Volume = Duration X Breadth X Width = 5 X 0.6 X 0.3 = 3.75 m3

For Column, If we have to calculate a concrete quantity for the  below Columns,

Typical ColumnTypical Circular Column

Rectangular Column, Volume = Elevation X Breadth X Width = 5 X 0.6 X 0.3 = 0.9 m3

Circular Column, Quantity = πr2 h= 3.141256 X (0.15)2 X 5 = 0.35 m3

Concrete Ingredients Calculation

For Cement, Coarse and sand Aggregate. 

It is a Volumetric Calculation.

Assuming we are in need of 2 m3 of concrete for M20 Cement Mix, (Combine Ratio, M20 = 1 : 1.5 : 3)

Total Area of the Concrete = 1+1.5+3 = 5.5 Parts

Therefore, Cement Volume = (Cement Part / Concrete Components ) * Concrete Volume

                                                 = (1/5.5)* Concrete Volume = (1/5.5)*2 = 0.3636 m3

Density of Cement = 1440 kg/ m3 = 0.3636 X 1440 = 523 kg = 10.5 Approx. Luggage

Sand Quantity = ( Sand Component / Concrete Parts ) * Concrete Quantity = (1.5/5.5) * 2 = 0.5454 m3

Coarse Aggregate = (Coarse Aggregate Part / Concrete Parts ) * Cement Volume

                                 = (3/5.5) * 2 = 1.09 m3

Water Cement Ratio

In accordance with IS 10262 (2009), Assuming Water-Cement Ratio for the Concrete since 0.45

Required Amount of Drinking water = W/C Ratio X Cement Quantity

Therefore, Drinking water = 0.45 X 0.3636 m3 = 0.16362 m3

Unit Weight of Drinking water = 1000 litres/m3

Required Amount of Drinking water = 0.16362 X 1000 = 163.62 litres

Therefore, we are in need of 10.5 bags of cement, 0.5454 m3 of sand, 1.09 m3 of Coarse aggregates and 163.62 litres of water.

Concrete ingredients Calculator

Hope you enjoyed this content.

Happy Learning 🙂





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