**A
load take down has revealed that the characteristic load at the column positions
is 3500 kN. A small site investigation has been undertaken and the
following reported:** * clay from ground level to 30m depth

- an SPT trend equal to 22 + 2z (z = depth below ground

level). - average Plasticity Index value of 35%

**Consider a 1.2m deep square pad footing:****R / A = 5.14 x Sc x Cu + q**-

- Sc = 1.2 for a square or circle (EC7: Appendix D)
- Cu = 99 + 9z = 109.8 kPa (as PI > 30 % use cu = 4.5 N cu base)
- q = 20 x 1.2 = 24 kPa (unit weight of soil = 20 kg/m3)
- (V / A) ult = (5.14 x 1.2 x 109.8) + 24 = 700 kPa
- (V / A)max = 700 / 2.5 = 280 kPa (Apply overall FoS of 2.5)
- A = 3500 / 280 = 12.5
*Use a 3.6m square pad***Check settlement:****? = q B (1

– ?2) Is / E**- q = 280 kPa - B = 3.6 m
- ? = 0.5
- Is= 1.2 (centre of a square foundation)
- Ev = 200 cu = 200 (99 + (9 x 1.2)) = 21960 kPa
- ? = (280 x 3.6 x (1 – 0.52) x 1.2) / 21960 = 41.2 mm
*Consider a 0.75m diameter*- Cu at base = 99 + (9 x 25) =

pile 25m long (contract pile tests will be done):

324 kPa - Cu ave = (99 + 324) / 2 = 211.5 kPa
- qs = ? cu ave = 0.60 x 211.5 = 126.9 kPa
- Qs = qs x As = 126.9 x 0.75 x ? x 25 = 7475 kN
- qb = Nc cu at base = 9 x 324 = 2916 kPa
- Qb = 2916 x 0.752 x ? x 0.25 =1288 kN
- (Qs+ Qb ) / 2.5 = 7475 + 1288) / 2.5 = 3505 kN
- Qs / 1.2 = 7475 / 1.2 = 6229 kN*Now: max pile load = 0.25 fcu A or fcu = (3500

/ 0.44) x 4 = 31818 kPa ( e.g use C35 concrete)***Check settlement using**- Load applied at 2/3 pile depth = 25 x 2/3 = 16.6m

equivalent raft: - Load spread a 1:4, so equivalent diameter = (2 x (16.6 / 4)) + 0.75) = 9.05m
- equivalent stress = 3500 / (9.052 x ? x 0.25) = 54.4 kPa
- ? = 0.5
- Is= 1.0 (centre of a circular foundation)
- Ev = 200 cu = 200 x (99 +( 9 x 16.6)) = 49680 kPa
- ? = (54.4 x 9.05 x (1 – 0.52) x 1.0) / 49680 = 7.4 mm